`A B C D E` is a regular pentagon and bisector of `/_B A E\ ` meets `C D\ ` at `Mdot` If bisector of `/_B C D` meets `A M` at `P ,` find `/_C P Mdot`

Explanation

In`A B C D E` pentagon
interior angle `=(5-2)xx180^0/5`
`=108^0`
in `ABCM` by angle sum
`/_B+/_C+/_BAM+/_AMC=360^0`
`108^0+108^0+54^0+/_AMC=360^0`
`/_AMC=90^0`
again in traingle `APM` by angle sum
`/_PMC+/_MCP+/_CPM=180^0`
`90^0+108^0/2+/_CPM=180^0`
`/_CPM=36^0`