The measure of angles of a hexagon are `x^@, (x-5)^@,(x-5)^@,(2x-5)^@,(2x-5)^@,(2x+20)^@` Find the value of `x`

Explanation

Given:The measure of angles of a hexagon are `x^@,\ (x-5)^@,\ (x-5)^@,\ (2x-5)^@,\ (2x-5)^@,\ (2x+20)^@`.
A regular hexagon has `6` sides.
Sum of all interior angles`=(n-2)times180^@`
Sum of all interior angles`=(6-2)times180^@`
Sum of all interior angles`=4times180^@=720^@`
Now,
Sum of all interior angles`=x^@+(x-5)^@+(x-5)^@+(2x-5)^@+(2x-5)^@+(2x+20)@`
Sum of all interior angles`=9x`
`720^@=9x`
`x=720^@/9`
`x=80^@`
Hence, the value of `x^@=80^@`.