A bag contains 5 red balls, 8 white balls, 4 green balls and 7 black balls. If one ball is drawn at random, find the probability that it is:
(i) black
(ii) red
(iii) not green

Explanation

(i) Number of Black Balls
Total Number of Balls `= 24`
Number of Black Balls `= 7`
`P(E)=7/24`
(ii) Red
Total Number of Balls `= 24`
Number of Red Balls `= 5`
`P(E)=5/24`
(iii) Numbers of Balls which are not green
P(E)`=20/24=5/6`