If the mass time and work are taken as fundamental physical quantities then dimensional formula of length

Options

A. `[m^(1/2)T^(1)W^(-1/2)]`
B. `[M^(-1/2)T^(1)W^(1/2)]`
C. `[M^(-1)T^(2)W]`
D. none of these

Answer

B

Explanation

`L=M^(a)T^(b)(ML^(2)T^(-2))^(c)`
`a+c=0`
` 2c=1`
`c=1/2 a= (-1)/2`
` b=2c=0 rArr b=1`