A conveyed belt of length lis moving with velocity v.a block of mass is pushed against the motion of conveyed belt with velocity `v_(0)` form end B Co- efficient of friction between block and belt is u the value of `v_(0)` so that the amount of heat liberated as a result of retardation of the block by conveyed belt is maximum is

Options

A. `sqrt(mugl)`
B. `sqrt(2mugl)`
C. `2sqrt(mugl)`
D. `sqrt(3mugl)`

Answer

B

Explanation

maximum heat will be generated when the distance travelled by the block with respect to the belt is maximum this will be the case when the block attains zero velocity after covering a distance l and then come phi back `a=mug`
` v_(2)=u^(2)-2a`
` 0=v_(0)^(2)-2xx(mug)l`
`v_(0)=sqrt2mugl`