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The conveyed belt is moving at 4m//s the...

The conveyed belt is moving at `4m//s` the coefficient of static friction between the conveyed belt and the 10kg package Bis ` mu_(s)=0.2 determine the shortest time in which the belt can be stopped so the the package does not slide on the belt

A

1s

B

2s

C

4s

D

8s

Text Solution

Verified by Experts

The correct Answer is:
B
`a_(max)=mu,g=0.2xx10=2m//s^(2)`
`t_(min)=u/a_(max)=4/2=2sec`
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