A satelite revolving in a circular equatorial orbit from west to east appears over a certain point on the equator every 8 hours therefore it's period is

Options

A. `16hr`
B. `8hr`
C. `6hr`
D. `32`

Answer

C

Explanation

`w_(E) - w_(s) = (2pi)/T`
`(2pi)/8-(2pi)/24=(2pi)/T`
`(2pi(3-1))/24=(2pi)/T`
`w_(s)-w_(E)=(2pi)/T`
`(2pi)/6-(2pi)/24=(2pi(4-1))/24 = (2pi)/8`
T_(satellite)=6hr`

`w_(S)-w_(E)=(2pi)/T`
`w_(S)-(2pi)/24 = (2pi)/8`
`w_(S)=2pi[1/24+1/8]`
`w_(S)= 2pi[(1+3)/24]`
`w_(s) = (2pi)/6`