A satellite is revolving round the earth with orbital speed `v_(0)` if it is imagined to stop suddenly the speed with which it will strike the surface of the earth would be `(v_(e)` - escape speed of a body from earth s surface)

Options

A. `v_(e)^(2)/v_(0)`
B. `v_(0)`
C. `(v_(e)^(2)-v_(0)^(2))^(1//2)`
D. `(v_(e)^(2)-2v_(0)^(2))^(1//2)`

Answer

D

Explanation

`v_(e)=sqrt((2GM)/R) V_(0)= sqrt((GM)/r)`
now `Delta ke =0 -1/2mv^(2)=(-(GMm)/R)-(-(GMm)/r)`
`-1/2mv^(2)=-1/2mv_(e)^(2)+mv_(0)^(2)`
`v=(v_(e)^(2)-2v_(0)^(2))^(1//2)`