A sphere of brass released in a long liquid column attains a terminal speed `v_(0)`. If the terminal speed attained by a sphere of marble of the same radius and released in the same liquid is `nv_(0)`, then the value of `n` will be (Given: The specific gravities of brass, marble and liquid are `8.5, 2.5` and `0.8`, respectively)

Options

A. `5/17`
B. `17/77`
C. `11/31`
D. `17/5`

Answer

B

Explanation

`v_(0)=2/gr^(2) ((8.5-0.8)g)/eta`
`nv_(0)=2/gr^(2)-((2.5-0.8)g)/eta`
`n=17//77`