Two moles of an idea gas is initially in state A having pressure `1.01xx10^(5)N//m^(2)` and temperature 3O0k keeping pressure constant the gas is taken to state B temperature at B is 500K the gas is then taken to state C in such a way that its temperature increases and volume decreases also from B To c the magnitude of `(dT)/(dV)` increases the volume of gas at C is equal to volume of gas at A now the gas is taken to initial state A keeping volume constant A total of 1200 J of heat is with drawn from the sample in the cyclic process the T-V graph for the cyclic process and work done in path B to C are respectively`(take R=8.3J//k//mol)`

Options

A.
B.
C.
D.

Answer

A

Explanation

In process AB pressure is constant `v propto T` that is we will obtain straight line in process BC temperature is increasing abd volume is decreasing A orB may be correct but in process CA volume is constant and work done in path Bto C is -4520J a is correct