Home
Class 12
PHYSICS
The magnitude of electric field intensit...

The magnitude of electric field intensity at point `B(2,0,0)` due to dipole of dipole moment, `vec(p)=hat(i)+sqrt(3)hat(j)` kept at origin is (assume that the point `B` is at large distance from the dipole and `k=(1)/(4pi epsilon_(0)))`

A

`sqrt(13k)/8`

B

`sqrt(13k)/4`

C

`sqrt(7k)/8`

D

`sqrt(7k)/4`

Text Solution

Verified by Experts

The correct Answer is:
C

`E=sqrt(E_(1)^(2)+E_(2)^(2))`
`=k/8sqrt((3+4))`
`=sqrt(7) k/8`
Promotional Banner

Topper's Solved these Questions

  • MASTER PRACTICE PROBLEM

    BANSAL|Exercise Comphrehension|134 Videos

  • MASTER PRACTICE PROBLEM

    BANSAL|Exercise Reasoning|75 Videos

  • FLUID MECHANICS

    BANSAL|Exercise PYQS AIEEE|10 Videos

  • SEMICONDUCTORS

    BANSAL|Exercise CBSE Question|32 Videos

Similar Questions

Explore conceptually related problems

The magnitude of electric field intensity at point B(x,0,0) due to a dipole of dipole moment , vec(P) - P_(0) ( hat(i) + sqrt(3)hat(j)) kept at origin is sqrt(n) ((kp_(0))/(r^(3))) , find n (assume that the point is at large distance form the diople , k = (1)/(4 pi in_(0)) .

The magnitude of electric field intensity at point (2,0,0) due to a dipole of dipole moment, vec P=hat i+sqrt(3)hat j kept at origin is where k=1/4 pi varepsilon_(0) is , (sqrt(m)k)/(n) then n-m is-

Find out the magnitude of electric field intensity and electric potential due to a dipole of dipole moment vec(P)=hat(i)+sqrt(3)hat(j) kept at origin at following points. (i) (2, 0, 0) (ii) (-1, sqrt(3), 0)

The electric field intensity vec(E) , , due to an electric dipole of dipole moment vec(p) , at a point on the equatorial line is :

The magnitude of electric field intensity at a point on the axis of short dipole is 30V/m. The distance of the point from the centre of the dipole is 2m. Then potential at that point is

An electric dipole of moment overset( r ) (p) = (hat(i) + 2hat ( j )) xx10^(-28) Cm is at origin. The electric field at point ( 2,4) due to the dipole is parallelto

Electric potential due to a dipole at a position vec r from its centre is: where (K = 1/(4pi epsilon_0)

An electric dipole with dipole moment vec p=(3hati +4hatj) C-m is kept in electric field vec E=0.4hatk N/C .What is the torque acting on it and the potential energy of the dipole?

Two point electric dipoles with dipole moment P_(1) and P_(2) are separated by a distance r with their dipole axes mutually perpendicular as shown. The force of interaction between the dipoles is (where k=(1)/(4piepsilon_(0)) )

BANSAL-MASTER PRACTICE PROBLEM-Additional topic
  1. The magnitude of electric field intensity at point B(2,0,0) due to dip...

    Text Solution

    |

  2. The manifestation of band structure in solids is due to

    Text Solution

    |

  3. When p-n junction diode is forward biased then

    Text Solution

    |

  4. If the ratio of the concentration of electron to that of holes in a se...

    Text Solution

    |

  5. If the lattice constant of this semiconductor is decreased, then which...

    Text Solution

    |

  6. In the following, which one of the diodes is reverse biased ?

    Text Solution

    |

  7. The circuit has two oppositively connected ideal diodes in parallel wh...

    Text Solution

    |

  8. If a p-n junction diode, a square input signal of 10 V is applied as s...

    Text Solution

    |

  9. In the circuit below, A and B represents two inputs and C represents t...

    Text Solution

    |

  10. A p-n junction (D) shown in the figure can act as a rectifier. An alte...

    Text Solution

    |

  11. The logic circuit shown below has the input waveforms ‘A’ and ‘B’ as s...

    Text Solution

    |

  12. The combination of gates shown below yields .

    Text Solution

    |

  13. Truth table for system of four NAND gates as shown in figure is : .

    Text Solution

    |

  14. In semiconductor the concentrations of electron and holes are 8xx10^(1...

    Text Solution

    |

  15. A potential difference of 2V is applied between the opposite faces of ...

    Text Solution

    |

  16. The main cause of avalence breakdown is

    Text Solution

    |

  17. A cube of germanium is placed between the poles of a magnet and a volt...

    Text Solution

    |

  18. In the given figure, which of the diodes are forward biased?

    Text Solution

    |

  19. Current in the circuit will be

    Text Solution

    |

  20. The diode used in the circuit shown in the figure has a constant volta...

    Text Solution

    |

  21. In the following circuits PN-junction diodes D(1), D(2) and D(3) are i...

    Text Solution

    |