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A neutral particle at rest in a magnetic...

A neutral particle at rest in a magnetic field decays into two charged particles of different mass. The energy released goes into their kinetic energy. Then what can be the path of the particles. Neglect any interaction between the two charges.

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
B

`R=(mv)/(qB)`
`q_(1)=-q_(2)`
`m_(1) v_(1) = m_(2)v_(2)`
`Rightarrow R_(1) = R_(2)`
but `m_(1)ne m_(2) Rightarrow omega_(1)=(qB)/m_(1) ne (qB)/m_(2)`
`Rightarrow omega` is not equal So collision does not occurat diametrically opposite point.
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