In the circuit shown, the capacitor is initially charged with a 12V battery, when switch `S_(1)` is open and switch `S_(2)` is closed. `S_(1)` is then closed and, at the same time, `S_(2)` is opened. The maximum value of current in the circuit is

Options

A. `0.38` mA
B. `0.84` mA
C. `0.72` mA
D. `0.1` mA

Answer

C

Explanation

`1/2Li^(2)=1/2Cvarepsilon^(2)`
`i=varepsilonsqrt(C/L)=12sqrt((9xx10^(-12))/(2.5xx10^(-3)))=(12xx3)/5 sqrt(10^(-8))`
`i=7.2xx10^(-4)A`