An object was placed upright 25cm in front of a converging lens with a focal length of 20cm. A concave mirror with a focal length of 15cm was placed 120cm behind the lens. Which of these describes the final image?

Options

A. real, enlarged
B. virtual, upright
C. virtual, inverted
D. inverted, diminished

Answer

A

Explanation

`I_(1)` is first image of lens and object for mirror & `I_(2)` is image of mirror and object for second refraction at lens. For refraction at lens
`1/V-1/((-25)) =1/20Rightarrow1/V -1/20-1/25=1/100`
`V=100`cm For mirror
`1/V+1/-20=(-1)/15`
`1/V=-1/60 Rightarrow V=-60cm`
For final refraction at lens (ray moving leftward)
`1/V+1/60=1/20`
`1/V=(3-1)/60`
`V=30`cm
Final magnification `=(-4)xx(-3)xx(-1//2)=-6`
Final image is real, inverted & enlarged.