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Statement-1: During flight under action ...

Statement-1: During flight under action of gravity, the change in velocity of a projectile in same time interval is same. (Neglect air friction) Statement-2: Neglecting air friction, the acceleration of projectile is constant during flight.

A

Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.

B

Statement-1 is true, statement -2 is true and statement -2 is NOT the correct explanation for statement-1.

C

Statement -1 is true, statement-2 is false.

D

Statement-1 is false, statement -2 is true.

Text Solution

Verified by Experts

The correct Answer is:
A
If particle moves with constant acceleration `vec(a)`, then change in velocity in every one second is numerically equal to `vec(a)` by defination. Hence statement-2 is true and correct explanation of statement-1.
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