Given figure is the part of some circuit. Charge on the capacitor in the circuit is given by `q=3(3-e^(-1))`, (coulomb) where `t` is time in seconds.
Let `V_(A)`, `V_(B)` and `V_(C)` be the potentials of points `A`, `B` and `C`, respectively. At `t=0` if `V_(A)=5 V` and a constant current `i_(0)=1 Amp` flows through `R=1Omega`, then find the `V_(P)` (in volt)

Explanation

`i=i_(0)+(dq)/(dt)`
`=1+3e^(-t)`