Figure shows a smooth cylindrical pulley of radius `R` with centre at origin of co-ordinates. An ideal thread is thrown over it on the two parts of ideal thread two identical masses are tied initially at rest with co-ordinates `(R,0)` and `(-R,-R)` respectively. If mass at `x-`axis is given slight upward jerk, it leaves contact with pulley at `(R cos phi, Rsinphi)`. Then find `phi//sinphi`.

Explanation

`mgRphi-mgRsinphi=1//2(2m)v^(2)`……(`i`)
`mv^(2)//R=mgsinphi`…..(`ii`)