A thermally insulated vessels contains two liquids with initial temperature `T_(1)` and `T_(2)` and specific heats `C_(0)` and `2C_(0)`, separted by a non conducting partition. The partition is removed, and the difference between the initial temperature of one of the liquids and the temperature `T` established in the vessel turns out to be equal to half the difference between the initial temperatures of the liquids. Determine the ratio of `M_(1)//M_(2)` of the masses of the liquids.

Explanation

`DeltaQ=0`
`C_(0)M_(1)(T-T_(1))+2C_(0)M_(2)(T-T_(2))=0`
`2(T_(1)-T)=2(T_(1)-T_(2))`
`(M_(1))/(M_(2))=(2C_(0))/(C_(0))=2`