Home
Class 11
PHYSICS
When the load on a wire increased slowly...

When the load on a wire increased slowly from `2 kg wt.` to `4 kg wt.`, the elogation increases from `0.6 mm` to `1.00 mm`. How much work is done during the extension of the wire? `[ g = 9.8 m//s^(2)]`

A

`14xx10^(-3)J`

B

`0.4xx10^(-3)J`

C

`8xx10^(-2)J`

D

`10^(-3)J`

Text Solution

Verified by Experts

`W=((1)/(2)F_(2)xxDeltal_(2))-((1)/(2)F_(1)xxDeltal_(1))=20xx10^(-3)-6xx10^(-3)=14xx10^(-3)J`
Promotional Banner

Topper's Solved these Questions

  • CONSERVATION OF MOMENTUM

    FIITJEE|Exercise Example|15 Videos

  • FLUID MECHANICS

    FIITJEE|Exercise Example|14 Videos

Similar Questions

Explore conceptually related problems

When the load on a wire is increased slowly from 1 kg wt to 2 kg wt the elongation increases from 0.2 mm to 0.3 mm. How much work is done during the extension ? (g=9.8m//s^(2))

When the load on a wire is increases from 0.61mm to 1.02mm. How much work is done during the extension of the wire ?

When the load on a wire is increased slowly from 4 to 8 kg, the elongation increases from 1.00 mm to 1.6 mm. If g = 10 m//s^(2) , then the work done during the extention of the wire is

When the load on a wire is slowly increased from 3 to 5 kg wt , the elongation increases from 0.61 to 1.02 mm . The work done during the extension of wire is

When load on a wire is increased from 4 kgf to 6 kgf, the elongation increases from 0.71 mm to 1.12 mm. Find the workdone during the extension of the wire.

When the load on a wire is increasing slowly from 2kg to 4kg, the elongation from 0.6mm to 1.2mm. The work done during this extension of the wire is (g=10m//s^(2))

When the load applied to stretch a wire is increased from 1kg-wt to 2kg-wt, the extention produced in the wire increases from 0.5 mm to 1mm. The work done in the extenstion of the wire is (g = 10 m//s^(2))

When the load applied to stretch a wire is increased from 1kg-wt to 2kg-wt, the extention produced in the wire increases from 0.5 mm to 1mm. The work done in the extenstion of the wire is (g = 10 m//s^(2))

When the weight on a string is change from 3.0 kg to 5.0 kgs the elengation changes from 0.61 mm to 1.02 mm. How much work is done during this extension of the string ? Find the Young's modulus of meterical of string if it is 1m in length and has a cross-sectional area 0.4 xx 10^(-4) m^2.