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An ideal choke takes a current of 8A whe...

An ideal choke takes a current of `8A` when connected to an a.c. source of `100` volt and `50Hz`. A pure resistor under the same conditions takes a current of `10A`. If two are connected in series to an `a.c.` supply of `100V` and `40Hz`, then the current in the series combination of above resistor and inductor is

A

`10A`

B

`8A`

C

`5sqrt(2)`amp

D

`10sqrt(2)`amp

Text Solution

Verified by Experts

`X_(L)=(100)/(8)`, `R=(100)/(10)=10Omega`
`Lxx100pi=(100)/(8)` or `L=(1)/(8pi)H`
`Z=sqrt(((1)/(8pi)xx2pixx40)^(2)+10^(2))=10sqrt(2)`
`I=(E)/(Z)=(100)/(10sqrt(2))=5sqrt(2)A`
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Knowledge Check

  • An ideal choke takes a current of 10 A when connected to an ac supply of 125 V and 50 Hz. A pure resistor under the same conditions takes a current of 12.5 A. If the two are connected to an ac supply of 100 V and 40 Hz, then the current in series combination of above resistor and inductor is

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    B
    (B) 12.5 A
    C
    (C) 20A
    D
    (D) 10A

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    A
    `10 A`
    B
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    `18A`
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