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Referring to the previous illustration w...

Referring to the previous illustration what will be the induced e.m.f at any instant if the loop is rotated an axis passing through the centre and parallel to the length ?

Text Solution

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The flux linked through the loop at any instant is
`phi` = BA cos `omega`t .
`therefore` the induced e.m.f at any instant is `epsilon = (d phi )/(dt)`
`rArr epsilon = -(d)/(dt)`(Blb cos `omega`t)
`rArr epsilon = `+(Blb `omega"sin"omega`t)
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