Home
Class 12
PHYSICS
The energy of electron in an excited hyd...

The energy of electron in an excited hydrogen atom is `-3.4eV`. Its angular momentum according to bohr's theory will be

A

`h//pi`

B

`h//2pi`

C

`nh//2pi`(`n` is an integer)

D

`2h//pi`

Text Solution

Verified by Experts

The energy of an electron in an orbit of principal quantum number `n` is given as
`E=(-13.6)/(n^(2))eV`
`rArr-3.4eV=(-13.6)/(n^(2))eV`
`rArr n^(2)=4rArr n=2`
The angular momentum of an electron in nth orbit is given as
`L=(nh)/(2pi)`, Putting `n=2`
We obtain `L=(2h)/(2pi)=(h)/(pi)`
Promotional Banner

Topper's Solved these Questions

  • MODERN PHYSICS

    FIITJEE|Exercise Illustration|10 Videos

  • MODERN PHYSICS

    FIITJEE|Exercise Solved Problems|10 Videos

  • MAGNETISM AND MATTER

    FIITJEE|Exercise ASSIGNMENT PROBLEMS OBJECTIVE : (LEVEL -II) (MULTI CHOICE SINGLE CORRECT)|20 Videos

  • OPTICS

    FIITJEE|Exercise NUMERICAL BASED QUESTIONS|2 Videos

Similar Questions

Explore conceptually related problems

The energy of an electron in excited hydrogen atom is -3.4 eV . Then, according to Bohr's therory, the angular momentum of the electron of the electron is

The energy of an excited hydrogen atom is 0.38 eV. Its angular momentum is n . h/(2pi) . Find n

What is the angular momentum of 5th orbit according to Bohr's theory ?

Energy of an electron in an excited hydrogen atom is -3.4eV . Its angualr momentum will be: h = 6.626 xx 10^(-34) J-s .

The energy of hydrogen atom in excited state is -3.4 eV. The angular momentum of electron is

The energy of an excited H-atom is -3.4eV . Calculate angular momentum of e^(-)

The energy of electron in first excited state of H -atom is -3.4 eV its kinetic energy is

Total energy of electron in an excited state of hydrogen atom is -3.4 eV . The kinetic and potential energy of electron in this state.