The elevation in boiling point, when 13.44g of freshly prepared `CuCl_(2)` are added to one kilogram of water, is [Some useful data, `K_(b)(H_(2)O)=0.52"kg K mol"^(-1),"mol.wt. of CuCl"_(2)=134.4gm]`

Options

A. 0.05
B. 0.1
C. 0.16
D. 0.21

Answer

C

Explanation

`DeltaT_(b)=[1+(n-1)alpha]xx(K_(b)W_("solute")xx1000)/(m_("solute")xxW_("solvent"))`
`=[1+(3-1)xx1]xx(0.52xx13.44xx1000)/(134.4xx1000)`
`=0.156`
`=0.16`