72.5g of phenol is dissolved in 1 kg of a solvent `(K_(f)=14)` which leads to dimerization of phenol and freezinfg point is lowered by 7 kelvin. What percentage of toal phenol is present in dimeric form?

Answer

35% phenol is present in demeric form

Explanation

`DeltaT_(b)=[1+((1)/(2)-1)alpha]xxK_(b)xx(W_("solute")xx1000)/(m_("solute")xxW_("solvent"))` lt brgt `7=[1+((1)/(2)-1)alpha]xx(14xx72.5xx1000)/(94xx1000)`
`a=0.704`
`~~70%`
`therefore`35% Phenol is present in diermic form.