Two liquids X and Y from an ideal solution at`300K`, Vapour pressure of the Solution containing `1`mol of X and `3`mol of Y is `550`mmHg . At the same temperature, if `1` mol of Y is further added to this solution ,vapour pressur of the solutions increases by `100`mmHg Vapour pressure (in mmHg) of X and Y in their pure states will be,respectively

Options

A. 200 and 300
B. 300 and 400
C. 400 and 600
D. 500 and 600

Answer

C

Explanation

`550=P_(x)^(0).(1)/(4)+P_(y)^(0).(3)/(4)` ………(i)
after adding 1 mole of y further
`560=P_(x)^(0).(1)/(5)+P_(y)^(0).(4)/(5)` …………(ii)
solving (i) & (ii) `P_(x)^(0)=400 MM`
`P_(y)^(0)=600 MM`