`49^x =7^3`

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Solve the following equation : 49xx7^x=(343)^(1/3) .

49xx49xx49xx49=7^(?)4b.7c.8d.16

If A is square matrix of order 3 and |A| = 7 then the value of |adj A| is a) 47 b) 7 c) 49 d) 7^(3)

find the value of (v) 6/49 × 7/3

Find the value of 'x' such that : 1/49xx7^(2x)=7^8

If 3y + 3 = 7x , then 21y - 49 x =

(49x - 63) + 7 = ___

Find the number of terms in the expansion of (4x - 7y)^49 + (4x + 7y)^49