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In an experiment four quantities a,b,c a...

In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow
`P = (a^(3)b^(2))/(cd) %` error in `P` is

A

`14%`

B

`10%`

C

`7%`

D

`4%`

Text Solution

Verified by Experts

The correct Answer is:
A
As given, `P = (a^(3)b^(2))/(cd)`
`:. (DeltaP)/(P) xx 100 = ((3Deltaa)/(a)+(2Deltab)/(b)+(Deltac)/(c)+(Deltad)/(d)) xx 100`
`=3 (Delta a)/(a) xx 100 +2(Deltab)/(b) xx 100 +(Deltac)/(c) xx 100+ (Deltad)/(d) xx 100`
`= 3 xx 1 +2 xx 2 +3 +4`
`= 3 +4 +3 +4 = 14%`
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