If the dimension of a physical quantity are given by `M^a L^b T^c,` then the physical quantity will be

Options

A. pressure if `a = b, b =- 1, c =- 2`
B. velocity is `a = 1,b = 0, c =- 1`
C. acceleration if `a = 1, b =1, c =- 2`
D. force if `a = 0, b =- 1, c =-2`

Answer

A

Explanation

(i) Dimensions of velocity `= [M^(0)L^(1)T^(-1)]`
Here, `a = 0, b = 1, c =- 1`
(ii) Dimensions of acceleration `[M^(0)L^(1)T^(-2)]`
Here, `a = 0, b = 1, c =- 2`
(iii) Dimensions of force `= [M^(1)L^(1)T^(-2)]`
Here, `a = 1,b = 1,T =- 2`
(iv) Dimensions of pressure `=[ML^(1)L^(-2)T^(-2)]`
`:.` Here, `a = 1, b =- 1,c =- 2`
`:.` The physical quantity is pressure.