If the error in the measurement of radius of a sphere in `2%` then the error in the determination of volume of the spahere will be

Options

A. `4%`
B. `6%`
C. `8%`
D. `2%`

Answer

B

Explanation

Volume of a sphere, `V = (4)/(3) pi r^(3)`
`:. (DeltaV)/(V) xx 100 = (3 xx Deltar)/(r) xx 100`
Here `(Deltar)/(r) xx 100 = 2%`
`:. (DeltaV)/(V) xx 100 = 3 xx 2% = 6%`