The dimensional formula for magnetic flux is

Options

A. `[ML^(2)T^(-2)A^(-1)]`
B. `[ML^(3)T^(-2)A^(-2)]`
C. `[M^(0)L^(-2)T^(2)A^(-2)]`
D. `[ML^(2)T^(-1)A^(2)]`

Answer

A

Explanation

Mathematically, magnetic flux
`phi = B A` ...(i)
but magnetic force
`F = Bil` or `B = (F)/(il)`
Putting the value of B in Eq.(i), we have
`phi = (F)/(il)A`
Thus, dimensions of `phi = ([MLT^(-2)][L^(2)])/([AL])`
`= [ML^(2)T^(-2)A^(-1)]`