An equation is given as `(p +(a)/(V^(2))) = b(theta)/(V)`,where `p=` pressure `V=` volumen and `theta =` absolute temperature. If a and b are constants, then dimensions of a will be

Options

A. `[ML^(5)T^(-2)]`
B. `[M^(-1)L^(5)T^(-2)]`
C. `[ML^(-5)T^(-1)]`
D. `[ML^(5)T]`

Answer

A

Explanation

From principle of homogeneity of dimensions. Dimensions of `p =` dimensions of `(a)/(V^(2))`
`p = (a)/(V^(2)) rArr a = pV^(2)`
`=[ML^(-1)T^(-2)] [L^(3)]^(2) = [ML^(5)T^(-2)]`