Percentage error in the measurement of mass and speed are 2% and 3% respectively. The error in the measurement of kinetic energy obtained by measuring mass and speed will be

Options

A. `12%`
B. `10%`
C. `8%`
D. `2%`

Answer

C

Explanation

Kinetic energy of `K = (1)/(2)mv^(2)`
`:. (DeltaK)/(K) xx 100 = (Deltam)/(m) xx 100 + 2xx (Deltav)/(v) xx 100`
Here, `(Deltam)/(m) xx100 = 2% rArr (Deltav)/(v) xx 100 = 3%`
`:. (DeltaK)/(K) xx 100 = 2% +2 xx 3% - 8%`