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Dimensional formula of self-inductance i...

Dimensional formula of self-inductance is

A

`[MLT^(-2)A^(-2)]`

B

`[ML^(2)T^(-1)A^(-2)]`

C

`[ML^(2)T^(-2)A^(-2)]`

D

`[ML^(2)T^(-2)A^(-1)]`

Text Solution

Verified by Experts

The correct Answer is:
C
As we know that emf induced in the inductors is given by `e = L(di)/(dt)`
`L = (edt)/(Di) = (W)/(q).(dt)/(di) = ([ML^(2)T^(-2)][T])/([AT][A]) = [ML^(2)T^(-2)A^(-2)]`
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Knowledge Check

  • The dimensional formula for inductance is

    A
    `[ML^2 T^(-2) A^(-2)]`
    B
    `[ML^2 TA^(-2)]`
    C
    `[ML^2T^(-1)A^(-2)]`
    D
    `[ML^2T^(-2)A^(-2)]`

  • Unit of self inductance is

    A
    `("Newton-second")/("Coulomb"xx"Ampere")`
    B
    `("Joule"//"Coulomb"xx"Second")/("Ampere")`
    C
    `("Volt"xx"metre")/("Coulomb")`
    D
    `("Newton"xx"metre")/("Ampere")`

  • The dimensional formula of resistance is:

    A
    `[LM^(2)T^(-2)A^(-2)]`
    B
    `[LM^(3)T^(-3)A^(-3)]`
    C
    `[LM^(2)T^(-2)A^(-2)]`
    D
    `[LM^(2)T^(-3)A^(-2)]`

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