A small block of mass `m=2kg` is at rest point `P` of the stationary wedge having frictionless hemispherical track of radius `R=4m`. The minimum constant acceleration `'a_(0)'` ( in `m//s^(2)`) is to be given to the wedge in horizontal direction, so that the small block just reaches the point `Q` as shown in figure. Assume all the contacts are frictionless and `g=10m//s^(2)`. If `a_(0)=2xm//s^(2)`. Find the value of `x`

Explanation

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