A heavy particle is tied ot the end A of a string of length `1.6m`. Its other end `O` is fixed. It revolves as a conical pendulum with the string making `60^(@)` with the vertical. Then `(g=10m//s^(2))`

Options

A. its period of revolution is `(2sqrt(2)pi)/5` sec
B. the tension in the string is double the weight of the particle.
C. the velocity of the particle `=sqrt(24)m//s`
D. the centripetal acceleration of the particle is `10sqrt(3)m//s^(2)`

Explanation

To solve the problem of a heavy particle tied to the end of a string and revolving as a conical pendulum, we will follow these steps:

### Step 1: Understand the Setup
We have a particle of mass \( m \) tied to a string of length \( L = 1.6 \, \text{m} \). The string makes an angle of \( 60^\circ \) with the vertical. The gravitational acceleration is given as \( g = 10 \, \text{m/s}^2 \).

### Step 2: Resolve Forces
The forces acting on the particle are:
- The tension \( T \) in the string acting along the string.
...