A capillary of internal radius `4 mm`, is dipped in water. To how much height, will the water rise in the capillary. (`T_(water) = 70 xx 10^(-3) N//m, g = 10 m//sec^(2), rho_(water) 10^(3) kg//m^(3)`, contact angle `theta rarr 0`)

Explanation

Capillary rise
`h = (2T)/(rhoPR)costheta = (2 xx 70 xx 10^(-3))/(10^(3) xx 10 xx 4 xx 10^(-3)) …(1)`
`h = 3.5 mm`