There is a small hole of diameter `0.1 mm` at the bottom of a large container. To what minimum height we can fill water in it. so that water doesn't come out of hole. `(T_(water) = 75 xx 10^(-3) N//m)rho_(water) = 10^(3) kg//m^(3), g = 10m//sec^(2)`

Explanation

the lower surface of water, which will try to come out will be spherical. Pressure just outside the spherical surface is :
`P_(0) + rhogh - (2T)/(R) costheta = P_(0)`
`h = (2T)/(rhogR) cos theta`
`(h)_(max) = (2T)/(rhogR)(cos theta)_(max)` and `(cos theta)_(max) = 1`
So `(h)_(max) = (2T)/(rhogR) = (2 xx 75 xx 10^(-3))/(10^(3) xx 10 xx 0.1 xx 10^(-3))`
`(h)_(max) = 15 cm`