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A spherical drop of water has 1mm radius...

A spherical drop of water has `1mm` radius. If the surface tension of the water is `50 xx 10^(-3) N//m` then find the difference of pressure between inside and outside the spherical drop is :

Text Solution

Verified by Experts

The correct Answer is:
`100N/m^(2)`
`P_(excess) = (2T)/(R) = (2(50 xx 10^(-3)))/(10^(-3)) = 100 N//m^(2)`
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