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There is a soap bubble of radius 2.4 xx ...

There is a soap bubble of radius `2.4 xx 10^(-4)m` in air cylinder at a pressure of `10^(5) N//m^(2)`. The air in the cylinder is compressed isothermal until the radius of the bubble is halved. Calculate the new pressure of air in the cylinder. Surface tension of soap solution is `0.08 Nm^(-1)`.

Text Solution

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Similar to question no. `37`,
`p_(2) = 8p_(1) + (245)/(c) = 8 xx 10^(5) + (24 xx .08)/(2.4 xx 10^(-4))`
`= 8.08 xx 10^(5) N//m^(2)`
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