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A glass tube of uniform internal radius ...

A glass tube of uniform internal radius `(r)` has a valve separating the two identical ends. Initially, the valve is in a tightly closed position. End `1` has a hemispherical soap bubble of radius `r`. End `2` has sub-hemispherical soap bubble as shown in figure. Just after opening the valve.

A

air from end `1` flows towards `2`. No change in the volume of the soap bubbles

B

air from end `1` flows towards end `2`. Volume of the soap bubble at end `1` decreases

C

no change occurs

D

air form end `2` flows towards end `1`. Volume of the soap bubble at end `1` increases.

Text Solution

Verified by Experts

The correct Answer is:
B
Pressure inside tube `= P = P_(0) + (4T)/(r)`
`:. P_(2) lt P_(1)` (since `r_(2) gt r_(1)`)
Hence pressure on side `1` will be greater than side `2`. So air from end `1` flows towards end `2`.
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