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Work done in increasing the size of a so...

Work done in increasing the size of a soap bubble from a radius of `3 cm` to `5 cm` is nearly. (surface tension of soap solution `= 0.3 Nm^(-1))`

A

`4pimJ`

B

`0.2pimJ`

C

`2pimJ`

D

`0.4 pi mJ`

Text Solution

Verified by Experts

The correct Answer is:
D
`W = TDeltaA`
`= 0.03 (2 xx 4pi xx (5^(2) - 3^(2))10^(-4)`
`= 24pi(16)xx 10^(-6)`
`= 0.384 pi xx 10^(-3)` Joule
`-= 0.4 pimJ`
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