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Two mercury drops (each of radius 'r') m...

Two mercury drops (each of radius `'r'`) merge to from bigger drop. The surface energy of the bigger drop, if `'T'` is the surface tension, is :

A

`4etar^(2)T`

B

`2etar^(2)T`

C

`2^(8//3) etar^(2)T`

D

`2^(5//3)etar^(2)T`

Text Solution

Verified by Experts

The correct Answer is:
C
`2.(4)/(3)pir^(3) = (4)/(3)piR^(3)`
`R = 2^(1//3)`
`S.E. = T.4piR^(2)`
`T4pi2^(2//3)r^(2)`
`T.2^(8//3)pir^(2)`.
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