A capillary of radius `r` is lowered into a wetting agent with surface tension `alpha` and density `d`. Determine the height `h_(0)` to which the liquid will rise in the capillary. Calculate the work done by surface tension and the potential enerfy acquired by the liquid in the capillary and compare the two. Explain the difference in the results obtained.

Answer

`[(2alpha)/(dgr),(4pir^(2))/(dg),(2pialpha^(2))/(dg)]`

Explanation

`piR^(2)h = piR_(1^(2))(h)/(2) , R_(1) = sqrt(2)R`
`mg = ((2T costheta)/(h)piR^(2)) rarr` for balancing the plate
`w + mg = ((4T costheta)/(h)2piR^(2)) rarr` '' plate `+` weight''
`w = (6 T cos theta pi R^(2))/(h) = (6 xx 0.49 xx cos 135^(@) pi (2 xx 10^(-2))^(2))/(0.38 xx 10^(-3))`
`= (12 pi cos 135^(@))/(38)kg`
`= 0.7 kg`