If the radius and surface tension of a spherical soap bubble are 'R' and 'T' respectively, Then show that the charge required to double its radius would be `8piR ,[epsilon_(0)R[7p_(0)R+12T]]^(1/2)`. Where `p_(0)` is the atmospheric pressure.

If r and T are radius and surface tension of a spherical soap bubble respectively then find the charge needed to double the radius of bubble.

If the radius and surface tension of a spherical soap bubble be r and T respectively. Find the charge uniformly distributed over the outer surface of the bubble, is required to double its radius. (Given that atmospheric pressure is P_(0) and inside temperature of the bubble during expansion remains constant.)

A soap bubble has radius R and surface tension S , How much energy is required to double the radius with out change of temperature .

A soap bubble of radius r and surface tension T is given a potential V. Show that the new radius R of the bubble is related with the initial radius by the equation P(R^(3) -r^(3)) +4T (R^(2)-r^(2)) = (in_(0)V^(2)R)/(2) where P is the atmospheric pressure.

If R is the radius of a soap bubble and S its surface tension, then the excess pressure inside is

If radius of a spherical bubble starts to increase with time t as r=0.5t . What is the rate of change of volume of the bubble with time t=4s ?

Surface tension of a soap solution is T. There is a soap bubble of radius r. The amount of charge that must be spread uniformly on its surface so that its radius becomes 2r is (8 pi r^(2))[varepsilon_(0)((KT)/(r)+7P_(0))]^(1/2)] Atmospheric pressure is P_(0) .Assume that air temperature made the bubble remains constant.Find value of K

The surface tension of soap is T . The work done in blowing a soap bubble of radius 3 R to that of a radius 5R is

The excess pressure inside a soap bubble P and the radius R of the bubble are related as

A soap bubble of radius 10^(-2) m is formed . The surface tension of the soap bubble is 0.04 N/m The excess of pressure inside the bubble is