A `50 kg` motor rests on four cylindrical rubber blocks. Each block has a height of `4 cm` and a cross-sectional area of `16 cm^(2)`. The shear modulus of rubber is `2 xx 10^(6) N//m^(2)`. A sideways force of `500 N` is applied to the motor. The distance that the motor moves sideways is

Options

A. `0.156 cm`
B. `1.156 cm`
C. `0.312 cm`
D. `0.204 cm`

Answer

A

Explanation

`(F)/(A) = eta(x)/(h)`
`(500)/(4 xx 16 xx 10^(-4)) = 2 xx 10^(6) rArr x = (5 xx 10^(-2))/(32)m = 0.156 cm`