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The compressibility of water is 46.4 xx ...

The compressibility of water is `46.4 xx 10^(-6)//atm`. This means that

A

the bulk modulus of water is `46.4 xx 10^(6)atm`

B

volume of water decrease by `46.4` one-millionths of the original volume for each atmosphere increase in pressure

C

when water is subjected to an additional pressure of one atmosphere, its volume decreases by `46.4`

D

when water is subjected to an additional pressure of one atmosphere, its volume decreases by `4.10^(6)` of its original volume.

Text Solution

Verified by Experts

The correct Answer is:
B
`46.4 xx 10^(-6)atm = (1)/(B)`
`B = (1)/(46.4 xx 10^(-4)) rArr B = (P)/(Deltav //v) rArr (Deltav)/(v) = (Deltap)/(B) = 46.4 xx 10^(-6)`
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