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The cross-section of a bar is given by [...

The cross-section of a bar is given by `[1 + (x^(2))/(100)]cm^(2)`, where `'x'` is the distance from one end. If the extension under a load of `'20 kN'` on a length of `10 cm` is `lambda xx 10^(-3) cm` then find `lambda`.
`Y = 2 xx 10^(5)N//mm^(2)`.

Text Solution

Verified by Experts

The correct Answer is:
`8`
`delta = (Fdx)/(AY). Deltal = int(Fdx)/(AY) = overset(10)underset(0)(int)(20 xx 10^(3)dx)/((1 + (x^(2))/(100)) xx 2 xx 10^(7))` = 0.008 cm`
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