Home
Class 11
PHYSICS
A 0.1 kg mass is suspended from a wire o...

A `0.1 kg` mass is suspended from a wire of negligible mass. The length of the wire is `1m` and cross-sectioal area is `4.9 xx 10^(-7)m^(2)`. If the mass Is pulled a little lin the vertically uniform eletric field strength `(81pi)/(7) xx 10^(5)Vm^(-1)`. When the field is swittched off, the drop is observed to fall with terminal veloctiy `2 xx 10^(-3)ms^(-1)`. given `g = 9.8 m s^(-2)`, viscosity of the air `= 1.8 xx 10^(-5)Nsm^(-2)` and the density of oil `= 900 m^(-3)`, the magnitude of `q` is :

Text Solution

Verified by Experts

The correct Answer is:
`4`
`omega_(n) = sqrt((k)/(m)) = sqrt((yA//l)/(m)) = sqrt((yA)/(lm)) rArr sqrt(((n xx 10^(9)) xx (4.9 xx 10^(-7)))/(1 xx 0.1)) = 140 rArr n = 4`
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY AND VISCOCITY

    RESONANCE|Exercise Exercise- 3 PART - IV|9 Videos

  • ELASTICITY AND VISCOCITY

    RESONANCE|Exercise Advanced Level Problems|9 Videos

  • ELASTICITY AND VISCOCITY

    RESONANCE|Exercise Exercise- 2 PART - III|11 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise dpp 92 illustration|2 Videos

  • ELECTROMAGNETIC INDUCTION

    RESONANCE|Exercise Exercise|43 Videos

Similar Questions

Explore conceptually related problems

A tiny spherical oil drop carrying a net charge q is balanced in still air with a vertical uniform electric field of strength (81pi)/(7)xx10^5Vm^-1 . When the field is switched off, the drop is observed to fall with terminal velocity 2xx10^-3ms^-1 . Given g=9.8ms^-2 , viscoisty of the air =1.8xx10^-5Nsm^-2 and the denisty of oil =900kg m^-3 , the magnitude of q is

A 0.1 kg mass is suspended from a wire of negligible mass. The length of the wire is 1 m and its cross - sectional area is 4.9xx10^(-7) m^(2) . If the mass is pulled a little in the vertically downward direction and released , it performs SHM with angular frequency 140 rad s^(-1) . If the young's modulus of the material of the wire is pxx10^(9) Nm^(-2) , find the value of p .

A 0.1kg mass is suspended from a wire of negligible mass. The length of the wire is 1m and its crosssectional are is 4.9xx10^-7m^2 . If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency 140 rad s^-1 . If the Young's modulus of the material of the wire is nxx10^9 Nm^-2 , the value of n is

A mass of 0.2 kg, length 1m and cross sectional area 4.9 xx 10^(-7) m^(2) is suspended from a massless wire. The mass is pulled slightly in the vertically downward direction and released. It performs simple harmonic motion of angular frequency 70 rad s^(-1) . If the Young's modulus of the material of the wire is x xx 10^(9) Nm^(-2) , find the value of x.

When 5 V potential difference is applied across a wire of length 0.1 m, the drift speed of electrons is 2.5 xx 10^(-4) ms ^(-1) . If the electron density in the wire is 8 xx 10^(28) m^(-3) , the resistivity of the material is close to :

A metal wire of negligible mass, length 1 m and cross-sectional area 10^(-6) m^(2) is kept on a smooth horizontal table with one end fixed on the table. A ball of mass 2kg is attached to the other end of the wire. When the wire and the ball are rotated with angular velocity of 20 rad/s, it is found that the wire is elongated by 10^(-3)m . If the Young's modulus of the metal is n xx 10^(11) N//m^(2) , then the value of n is

When 5 V potential difference is applied across a wire of length 0.1 m. The drift speed of electrons is 2.5 xx 10^(-4) ms^(-1) . If the electron density in the wire is 8 xx10^(28) m^(-3) , calculate the resistivity of the material of wire

A body of mass 1 kg is fastened to one end of a steel wire of cross- section area 3 xx 10^(-6)m^(2) and is rotated in horizantal circle of radius 20 cm with a constant speed 2 m//s . Find the elongation of the wire (Y= 2 xx 10^(11) N//m^(2))

A particle of mass 6.4xx10^(-27) kg and charge 3.2xx10^(-19)C is situated in a uniform electric field of 1.6xx10^5 Vm^(-1) . The velocity of the particle at the end of 2xx10^(-2) m path when it starts from rest is :