Ionic radii of :

Options

A. `Ti^(4-) lt Mn^(-)`
B. `.^(35)Cl^(-) lt .^(37) Cl^(-)`
C. `K^(-) gt Cl^(-)`
D. `P^(3-) gt P^(5+)`

Answer

D

Explanation

(a) `Ti^(4+) gt Mn^(7+)` is the correct order of size due to lower positive charge on `Ti^(4+)`
(b) `.^(37)Cl^(-)=.^(37)Cl^(-)`: Isotopes with same charge have same size because isotopes differ in compositions of nuclei which do not affect the atomic/ionic radius.
(c) `K^(+) lt Cl^(-)` is the correct order. Among isoelectronic species, anion has greater size than cation.
(d) `P^(3+) gt P^(5+)` is the correct order. For the same elements, lower the positive charge, larger the ions.