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The height at which the acceleration due...

The height at which the acceleration due to gravity becomes `(g)/(9)` (where g =the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :

A

`(R )/(sqrt(2))`

B

R/2

C

`sqrt(2)R`

D

2R

Text Solution

Verified by Experts

The correct Answer is:
D
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